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Can You Solve This? I-Math 6-year-olds can.

The curriculum helps a child visualize & understand the problem

Question:

In a cage, there are 8 animals, some are ducks while some others are cows.Together we can see 20 legs. Find out how many are Ducks and how many Cows?

Solution:

  • Let the number of Ducks be X
  • Let the number of Cows be Y
  • Therefore
  • (Ducks + Cows) = (X + Y) = 8 - Equation (a)
  • Cows have 4 legs and Ducks have 2 legs
  • Therefore,
  • 2X + 4Y = 20 - Equation (b)
  • From Equation (a), X = 8 - Y

Substituting the value of X in Equation (b), we get:

  • 2(8 - Y) + 4Y = 20
  • 16 - 2Y + 4Y = 20
  • 16 + 2Y = 20
  • 2Y = 20 - 16 i.e. 2Y = 4 i.e. Y = 2

Substituting the value of Y in Equation (a)

  • X + 2 = 8 i.e. X = 8 � 2 i.e. X = 6
  • ANSWER
  • Number of Ducks = X = 6
  • Number of Cows = Y = 2

Another method of solving the problem

This method helps the child to visualize & understand the problem completely

The question says that there is a cage, let us draw a cage.

There are 8 animals , let us draw 8 ovals.
Together we can see 20 legs.
For any animal to have 4 legs, it needs to have 2 legs first.
Accordingly, let us draw the legs and count.
16 legs; yet 4 remains
Draw the remaining 4 legs

ANSWER: 2 Cows & 6 Ducks

The problem is never in the problem, it is in the understanding of the problem. Once the child understands the problem completely, half the problem is solved.
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