## Can You Solve This? I-Math 6-year-olds can.

### The curriculum helps a child visualize & understand the problem

#### Question:

In a cage, there are 8 animals, some are ducks while some others are cows.Together we can see 20 legs. Find out how many are Ducks and how many Cows?

#### Solution:

- Let the number of Ducks be X
- Let the number of Cows be Y
- Therefore
- (Ducks + Cows) = (X + Y) = 8 - Equation (a)
- Cows have 4 legs and Ducks have 2 legs
- Therefore,
- 2X + 4Y = 20 - Equation (b)
- From Equation (a), X = 8 - Y

#### Substituting the value of X in Equation (b), we get:

- 2(8 - Y) + 4Y = 20
- 16 - 2Y + 4Y = 20
- 16 + 2Y = 20
- 2Y = 20 - 16 i.e. 2Y = 4 i.e. Y = 2

#### Substituting the value of Y in Equation (a)

- X + 2 = 8 i.e. X = 8 � 2 i.e. X = 6
- ANSWER
- Number of Ducks = X = 6
- Number of Cows = Y = 2

### Another method of solving the problem

This method helps the child to visualize & understand the problem completely

The question says that there is a cage, let us draw a cage.

There are 8 animals , let us draw 8 ovals.

Together we can see 20 legs.

For any animal to have 4 legs, it needs to have 2 legs first.

For any animal to have 4 legs, it needs to have 2 legs first.

Accordingly, let us draw the legs and count.

16 legs; yet 4 remains

Draw the remaining 4 legs

ANSWER: 2 Cows & 6 Ducks

The problem is never in the problem, it is in the understanding of the problem. Once the child understands the problem completely, half the problem is solved.

16 legs; yet 4 remains

Draw the remaining 4 legs

ANSWER: 2 Cows & 6 Ducks

The problem is never in the problem, it is in the understanding of the problem. Once the child understands the problem completely, half the problem is solved.